How do you rewrite #(-7)^-1# without the exponent?

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Answer 1 · 2017-02-22T20:22:45

#-1/7#

Before we get rid of the exponent, we need to change it. Take a look at the rule below:

#a^-b = 1/(a^b)#

Given this law, let's apply it to the problem.

#-7^-1 = 1/(-7^1)#

Now that we got rid of the negative, we can eliminate the exponent as a whole. Recall that anything to the first power is itself.

#1/(-7)#

This can be rewritten as:

#-1/7#