How do you rewrite each explicit formula in function form #g_n=-6*(1/3)^(n-1)#?

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Answer 1 · 2018-01-13T11:25:04

The geometric sequence is #-6 , -2 , -2/3 , -2/9 ....#

#g_n = -6 (1/3)^(n-1)#

#g_1 = -6 (1/3)^(1-1) = -6*1= -6#

#g_2 = -6 (1/3)^(2-1) = -6* 1/3= -2#

#g_3= -6 (1/3)^(3-1) = -6* (1/3)^2=-2/3#

#g_4= -6 (1/3)^(4-1) = -6* (1/3)^3=-2/9#

The geometric sequence is #-6 , -2 , -2/3 , -2/9 ....#

First term is #g_1= -6# , common ratio is #r= -1/3# [Ans]