Question

How do you rewrite `log_(1/3)x` as a ratio of common logs and natural logs?

Answer 1

I tried this:

Explanation:

We can change into an new base `c` base as:

`log_ab=log_cb/log_ca`

so in your case we get:

• common log:

`log_(1/3)x=log_(10)x/log_(10)(1/3)`

• natural log:

`log_(1/3)x=log_ex/log_e(1/3)`