How do you rewrite #y=-3x^2-12x-2# rewritten in vertex form?

1 Answer
Oct 22, 2017

# y = -3(x-2)^2 + 10#

Explanation:

Vertex form of quadratic equation #ax^2 + bx + c # is
#y = a(x - x_s)^2 + y_s#

#x_s = -b / (2a)#

#y_s = -(b^2/4a) + c#

Given equation is
#y = -3x^2 -12x -2#
#a = -3, b = -12, c = -2#

#x_s =( -12) / (2*(-3)) = 2#
#y_s = -b^2/(4a) + c =-( -12^2) / (4 * -3) + (-2)= 10#

#y = -3 * ( x - 2)^2 + 10#