How do you simiplify #\sqrt { 320p ^ { 3} q r }#?

1 Answer
Jun 12, 2017

Answer:

#= 8sqrt5 p^2 sqrt(pr#

Explanation:

#sqrt(320p^3qr)#

#= sqrt320 xx sqrt(p^3) xx sqrtq xx sqrtr#

#= sqrt320 xx p^2 xx sqrtq xx sqrtr#

#= 8sqrt5 xx p^2 xx sqrtq xx sqrtr#

#= 8sqrt5 p^2sqrt(qr#

#therefore sqrt(320p^3qr)- "simplified" = 8sqrt5 p^2sqrt(qr#

All the best!