How do you simiplify #\sqrt { 320p ^ { 3} q r }#?

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Answer 1 · 2017-06-12T01:34:32

#= 8sqrt5 p^2 sqrt(pr#

#sqrt(320p^3qr)#

#= sqrt320 xx sqrt(p^3) xx sqrtq xx sqrtr#

#= sqrt320 xx p^2 xx sqrtq xx sqrtr#

#= 8sqrt5 xx p^2 xx sqrtq xx sqrtr#

#= 8sqrt5 p^2sqrt(qr#

#therefore sqrt(320p^3qr)- "simplified" = 8sqrt5 p^2sqrt(qr#

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