How do you simplify #(1 - 1/3)/ (1/2 - 1/6)#?

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Answer 1 · 2018-02-01T05:47:49

2

Numerator #Nr = (1/1) - (1/3)#

3 is the L C M of 1 & 3

#Nr = ((1*3) -1) /3 = (3 - 1) / 3 = 2/3#

Denominator #Dr = (1/2) - (1/6)#

6 is the L C M of 2 & 6

#Dr = ((1 * cancel(6/2) 3)- (1)) / 6 = (3 - 1) / 6 = (cancel(2)1)/(cancel(6)3) = 1/3#

Now dividing Nr by Dr,

#(Nr) / (Dr)= (2/3) / (1/3) = (2/cancel3) * (cancel3/1) = 2/1 = 2#