How do you simplify #((-1+2i)(5-4i)) / ((1-2i)(5+4i))#?

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Answer 1 · 2016-07-20T18:23:26

#-9/41+40/41i#

The Given Exp.#=(-cancel((1-2i))(5-4i))/(cancel((1-2i))(5+4i))#

#=-(5-4i)/(5+4i)xx(5-4i)/(5-4i)#

#=-(5-4i)^2/{5^2-(4i)^2}#

#=-(25-40i+16i^2)/{25-16i^2}#

#=-(25-40i-16)/(25+16)#

#=-(9-40i)/41#

#=-9/41+40/41i#