How do you simplify #(1.8times10^-3)/(9times10^2)# in scientific notation?

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Answer 1 · 2016-03-22T09:54:00

#2xx10^(-6)#

Given:#" "(1.8xx10^(-3))/(9xx10^2)#..................(1)

If we can change the 1.8 so that it looks like 18 then #18/9=2#

#1.8" is the same as "18/10#

and #18/10" is the same as "18xx10^(-1)#

So rewrite expression (1) as#" " (18xx10^(-1)xx10^(-3))/(9xx10^2)" "...(1_a)#

Note that #" " 1/10^2# is the same as#" " 10^(-2)#

So rewrite expression #(1_a)# as:

#18/9xx10^(-1)xx10^(-3)xx10^(-2)#

Giving:#color(blue)(color(brown)(" "2xx10^(-1-3-2)) = 2.0xx10^(-6))#