How do you simplify #1/root3(x^2)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer sankarankalyanam Jun 15, 2018 #color(orange)(=> x^(-2/3)# Explanation: #(1/root 3 (x^2))# #=> 1 / (x*2)^(1/3)# #"As per theory of indices", (a^m)^n = a^(mn), 1/a^m = a^-m# #:. => 1 / x^(2/3) = x^(-2/3)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1457 views around the world You can reuse this answer Creative Commons License