How do you simplify #(1-sqrt3) (3+ sqrt2)#?

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Answer 1 · 2016-02-07T09:19:30

#3+sqrt2-3sqrt3-sqrt6#

Use the FOIL method of multiplying Binomials:
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#(1-sqrt3)(3+sqrt2)#

#ul Firsts#

#rarr=1*3=3#

#ul Outer#

#rarr=1*sqrt2=sqrt2#

#ul I##n##n##er#

#rarr=-sqrt3*3=-3sqrt3#

#ul L##a##st#

#rarr=-sqrt3*sqrt2=-sqrt6#

Now put them all together:

#(1-sqrt3)(3+sqrt2)=3+sqrt2-3sqrt3-sqrt6#