How do you simplify #1/(sqrta+sqrtb)#?

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Answer 1 · 2018-05-13T12:41:35

#(sqrta-sqrtb)/(a-b)#

Expression #= 1/(sqrtx+sqrtb)#

Rationalise the denominator:

Expression #= 1/(sqrtx+sqrtb) xx (sqrta - sqrtb)/ (sqrta - sqrtb)#

#= (sqrta-sqrtb)/(a-b)#

Answer 2 · 2018-05-13T12:42:45

On simplification it would be#(sqrta-sqrtb)/(a-b) #

We have
#1/(sqrta+sqrtb)#
Multiplying and diving by #sqrta-sqrtb#
We get #(sqrta-sqrtb)/(a-b)# which is the possible simplest form.