Question

How do you simplify `10^(log sqrt x )`?

Answer 1

`sqrtx`
(Assuming `log = log_10`)

Explanation:

Consider:`a=10^b -> log_10 a =b`

In this example: `y = 10^(log_10sqrtx)`

So, `a=y` and `b=log_10 sqrtx` in this case

`:. log_10 y = log_10 sqrt(x)`

Hence `y=sqrtx`