How do you simplify #(10*sqrt8) /sqrt 16#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Leland Adriano Alejandro Feb 11, 2016 #(10sqrt8)/sqrt16=5sqrt2# Explanation: #(10sqrt8)/sqrt16=(10sqrt8)/4=(10sqrt(4*2))/4=(5*2*sqrt(4)*sqrt(2))/(2*2)# #=(5*2*2*sqrt(2))/(2*2)# #=(5*cancel2*cancel2*sqrt(2))/(cancel2*cancel2)# #=5sqrt2# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1070 views around the world You can reuse this answer Creative Commons License