How do you simplify #(101!)/(99!)#?

1 Answer
Narad T.
Oct 26, 2016

The answer is #10100#

Explanation:

6...We look at the factorial
#101! =101*100*99*98..........1#
and
#99! =99*98*97.........1#

So the division is #(101!) /(99!)=(101*100*99*98..........1)/(99*98*97.........1)=101*100=10100#

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