How do you simplify # ( 10sqrt 2)/(2 sqrt 8)#?

2 Answers
Apr 16, 2016

#(18sqrt2)/(2sqrt8)=(9sqrt2)/(2sqrt2)=4.5#

Apr 16, 2016

#+-5/2#

Explanation:

Write as

#(10sqrt(2))/(2sqrt(2)sqrt(4)) -> (10 sqrt(2))/(4sqrt(2))->10/4xx1 = 5/2#

Consider: #(-a)xx(-a)=(+a)xx(+a)=a^2#. The example's #a^2# is the equivalent condition to the 8 and 2 in #sqrt(2)" and "sqrt(8)#. So in our solution the square root cane be positive or negative. Thus our answer is:

#" "+-5/2#