How do you simplify #12^-3*12^10*12^0#?

1 Answer
Jim G.
May 25, 2016

#12^7=35 831 808#

Explanation:

Using the #color(blue)"rules of indices or exponents"#

#color(red)(|bar(ul(color(white)(a/a)color(black)(a^mxxa^n=a^(m+n))color(white)(a/a)|)))#

#a " is called the"color(blue)" base"#

m and n are called the #color(blue)"indices or exponents"#

As long as the bases are the same then we can simplify by adding the indices together.

#rArr12^-3xx12^10xx12^0=12^(-3+10+0)=12^7#

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