How do you simplify #(12sqrt2)^2#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer man k. May 12, 2018 288 Explanation: #(12sqrt(2))^2# = #(12sqrt2)(12sqrt2)# =#(12)(12)(sqrt2)(sqrt2)# #(12)(12)((sqrt2)^2# =#(12)(12)(2)# =#288# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 2314 views around the world You can reuse this answer Creative Commons License