How do you simplify √150 ÷ √3? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Don't Memorise Jul 23, 2015 #=color(blue)(5sqrt2# Explanation: Prime factorising: #sqrt150 = sqrt(3*5*2*5)# #=5sqrt6# Now: #sqrt150/sqrt3 = (5sqrt6)/sqrt3# #sqrt 6 =sqrt2 * sqrt3# So, # (5sqrt6)/sqrt3 = (5cancelsqrt3*sqrt2)/cancelsqrt3# #=color(blue)(5sqrt2# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 2183 views around the world You can reuse this answer Creative Commons License