How do you simplify #(16sqrt21) / (2sqrt7)#?
2 Answers
May 9, 2018
Explanation:
#"using the "color(blue)"law of radicals"#
#•color(white)(x)sqrta/sqrtbhArrsqrt(a/b)#
#rArr16/2xxsqrt21/sqrt7=8xxsqrt(21/7)=8sqrt3#
May 9, 2018
#(16sqrt21)/(2sqrt7)=13.856#
Explanation:
Given -
#(16sqrt21)/(2sqrt7)#
#16/2xxsqrt21/sqrt7#
#16/2xx(sqrt21)^2/(sqrt7)^2#
#16/2xx21/7#
#8xxsqrt3=8 xx 1.732=13.856#
#(16sqrt21)/(2sqrt7)=13.856#