# How do you simplify (16x^3)/(5y^9)*(x^5y^8)/(80x^3y)?

Aug 9, 2016

$\frac{{x}^{5}}{25 {y}^{2}}$

#### Explanation:

Simplify the numbers as for a normal fraction question. Use laws of indices to simplify the indices in the numerator and in the denominator, then simplify again for the final answer.

$\frac{\cancel{16} {x}^{3}}{5 {y}^{9}} \cdot \frac{{x}^{5} {y}^{8}}{{\cancel{80}}^{5} {x}^{3} y}$ =

=(x^8y^8)/(25x^3y^10

=$\frac{{x}^{5}}{25 {y}^{2}}$