How do you simplify #18sqrt12div9sqrt3 #? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Don't Memorise Sep 14, 2015 #color(blue)(4# Explanation: #(18sqrt12) /( 9sqrt3# #sqrt 12 # can be simplified by prime factorising #12# #sqrt 12 = sqrt(3 *2^2) = color(blue)(2sqrt3# Now the expression can be written as: #(18sqrt12) /( 9sqrt3) = ( 18 * color(blue)(2sqrt3))/(9sqrt3 # #=(cancel36cancelsqrt3) / (cancel9cancelsqrt3) = color(blue)(4# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 995 views around the world You can reuse this answer Creative Commons License