How do you simplify #(2/15)(25/49)(-63/72)#?

2 Answers
Feb 5, 2018

Answer:

#-5/84#

Explanation:

#"note that "-63/72" can be simplified"#

#"by "color(blue)"cancelling "" numerator/denominator by 9"#

#rArr-63/72=-cancel(63)^7/cancel(72)^8=-7/8#

#"thus the calculation becomes"#

#2/15xx25/49xx-7/8#

#"simplify further by cancelling 2/8, 15/25 and 7/49"#

#cancel(2)^1/cancel(15)^3xxcancel(25)^5/cancel(49)^7xx-cancel(7)^1/cancel(8)^4#

#"multiply the remaining values on the "#
#"numerator/denominator"#

#=(1xx5xx-1)/(3xx7xx4)=-5/84#

Feb 5, 2018

Answer:

#-5/84#

Explanation:

Start by cancelling with any common factors in the numerators and denominators.

#2/15 xx25/49 xx-63/72#

# div 5 (15 and 25)and div 7 (49 and 63)#

#=-2/cancel15^3 xxcancel25^5/cancel49^7 xxcancel63^9/72#

#=-cancel2/3 xx5/7 xxcancel9/(cancel72^(cancel8^4))#

# div 9 (9 and 72) and div 2 (2 and 8)#

#=5/(3xx7xx4)#

#= -5/(84)#

There are different ways of cancelling. The order is not important.

This is easier than multiplying all the tops together and all the bottoms together and then trying to simplify.