# How do you simplify 2 / (3 + i)?

Multiply and divide with the conjugate of the denominator $3 - i$
2 / (3 + i)=2*(3-i)/[(3+i)(3-i)]=2*((3-i)/[9-i^2])=2*(3-i)/10= 2/10*(3-i)
Remember that ${i}^{2} = - 1$