Question

How do you simplify `2 / (3 + i)`?

Answer 1

Multiply and divide with the conjugate of the denominator `3-i`

hence

#2 / (3 + i)=2*(3-i)/[(3+i)(3-i)]=2*((3-i)/[9-i^2])=2*(3-i)/10= 2/10*(3-i)#

Remember that `i^2=-1`