How do you simplify #(2.548times10^5)/(2.8times10^-2)#?

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Answer 1 · 2017-02-28T20:04:38

Shown with a lot of detail and trying not to use a calculator.

#9.1xx10^6#

Note that #1/(10^(-2)# is the same as #10^2#

So now we have:

#2.548/2.8xx10^5xx10^2" "=" "2.548/2.8xx10^7#

Do not like decimals so lets get rid of them. For the moment disregard the #10^7#

#color(green)(2.548/2.8color(red)(xx1)" "->" "2.548/2.8color(red)(xx1000/1000)" "=" "2548/2800)#

Putting it all together we have:

#2548/2800xx10^7#

#91/100xx10^7#

#9.1/10xx10^7#

#9.1xx10^7/10#

#9.1xx10^6#