How do you simplify #(-2-5i)/(3i) #?

1 Answer
Apr 21, 2016

Answer:

Multiply by #i/i#, eliminating #i# from the denominator to find

#(-2-5i)/(3i)=-5/3+2/3i#

Explanation:

To remove the imaginary component from the denominator, we can multiply the numerator and the denominator by #i# and then simplify from there.

#(-2-5i)/(3i) = ((-2-5i)*i)/(3i*i)#

#=(-2i-5i^2)/(3i^2)#

#=(5-2i)/(-3)#

#=-5/3+2/3i#