How do you simplify $(- 2 + 5 i) + (- 4 - 2 i)$ $(-2 + 5i) + (-4 - 2i)$ and write in a+bi form?

Question

3053 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-12-26T12:24:18

$- 6 + 3 i$ $-6 + 3i$

When you add two complex numbers together, you have to add their real parts together and their imaginary part together.

So $(- 2 + 5 i) + (- 4 - 2 i) = (- 2 + (- 4)) + i (5 - 2) = - 6 + 3 i$ $(-2 + 5i) + (-4 - 2i) = (-2 + (-4)) +i(5-2) = -6 + 3i$

How do you simplify (-2 + 5i) + (-4 - 2i) (−2+5i)+(−4−2i) (-2 + 5i) + (-4 - 2i) and write in a+bi form?