# How do you simplify  (-2 + 5i) + (-4 - 2i)  and write in a+bi form?

$- 6 + 3 i$
So $\left(- 2 + 5 i\right) + \left(- 4 - 2 i\right) = \left(- 2 + \left(- 4\right)\right) + i \left(5 - 2\right) = - 6 + 3 i$