How do you simplify #2 + 7i div 1-3i#? Precalculus Complex Numbers in Trigonometric Form Division of Complex Numbers 1 Answer SagarStudy Jan 12, 2016 #(2+7i)/(1-3i)# Multiply and divide by #1+3i#. #implies (2+7i)/(1-3i)=((2+7i)(1+3i))/((1-3i)(1+3i))=(2+6i+7i+21i^2)/(1-9i^2)=(2+13i-21)/(1+9)=(-19+13i)/10=-19/10+(13i)/10# #implies (2+7i)/(1-3i)=-19/10+(13i)/10# Answer link Related questions How do I graphically divide complex numbers? How do I divide complex numbers in standard form? How do I find the quotient of two complex numbers in polar form? How do I find the quotient #(-5+i)/(-7+i)#? How do I find the quotient of two complex numbers in standard form? What is the complex conjugate of a complex number? How do I find the complex conjugate of #12/(5i)#? How do I rationalize the denominator of a complex quotient? How do I divide #6(cos^circ 60+i\ sin60^circ)# by #3(cos^circ 90+i\ sin90^circ)#? How do you write #(-2i) / (4-2i)# in the "a+bi" form? See all questions in Division of Complex Numbers Impact of this question 2119 views around the world You can reuse this answer Creative Commons License