How do you simplify #(2.88times10^3)/(1.2times10^-5)#?
1 Answer
Apr 15, 2017
Explanation:
We can 'split' the numerator/denominator into the product of separate parts as follows.
#rArr(2.88xx10^3)/(1.2xx10^-5)#
#=(2.88)/(1.2)xx10^3/10^-5#
#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(a^m/a^n=a^(m-n))color(white)(2/2)|))) #
#=2.4xx10^((3-(-5)))=2.4xx10^8#
