How do you simplify $(2+i) / (3+i)$ ?

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Answer 1 · 2015-12-18T02:56:30

$7/10+1/10i$

Multiply by the complex conjugate of the denominator.

$(2+i)/(3+i)((3-i)/(3-i))=(6+i-i^2)/(9-i^2)$

Recall that since $i=sqrt(-1),color(red)(i^2=-1$ .

$=(6+i-(-1))/(9-(-1))=(7+i)/10=7/10+1/10i$

How do you simplify (2+i) / (3+i) (2+i) / (3+i)?