How do you simplify #2pq^2-:q#?

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Answer 1 · 2016-11-19T20:30:51

#2pq#

Expressing as a fraction.

#rArr(2xxpxxq^2)/q=(2pq^2)/q#

Cancel q from the numerator/denominator.

#=(2pcancel(q^2)^q)/cancel(q)^1=(2pq)/1=2pq#

How do you simplify #2*p*q^2-:q#?