How do you simplify #-2(r-4s-6t)#?

1 Answer
smendyka
Dec 29, 2016

#-2r + 8s + 12t#

Explanation:

To solve this you multiply each term within the parenthesis by #color(red)(-2)# You need to ensure you handle the sign of each term correctly:

#(color(red)(-2) xx r) + (color(red)(-2) xx -4s) + (color(red)(-2) xx - 6t)#

#(-2r) + (+8s) + (+12t)#

#-2r + 8s + 12t#

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