How do you simplify #2 sqrt 27 - 4 sqrt 3#?

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Answer 1 · 2016-04-07T09:21:31

#= 2sqrt3#

#2sqrt27 - 4sqrt3#

We first simplify #27# by prime factorisation. (express a number as a product of its prime factors)

#27 = 3 * 3 * 3 #

So, #sqrt(27) = sqrt (3 * 3 * 3 ) = sqrt ( 3^2 * 3 ) = color(green)( 3sqrt3 #

#2sqrt27 - 4sqrt3 = 2 * color(green)( 3sqrt3 )- 4sqrt3#

#= 6 sqrt3 - 4sqrt3#

#= 2sqrt3#