How do you simplify #2 sqrt 27 - 4 sqrt 3#?

1 Answer
Apr 7, 2016

Answer:

#= 2sqrt3#

Explanation:

#2sqrt27 - 4sqrt3#

We first simplify #27# by prime factorisation. (express a number as a product of its prime factors)

#27 = 3 * 3 * 3 #

So, #sqrt(27) = sqrt (3 * 3 * 3 ) = sqrt ( 3^2 * 3 ) = color(green)( 3sqrt3 #

#2sqrt27 - 4sqrt3 = 2 * color(green)( 3sqrt3 )- 4sqrt3#

#= 6 sqrt3 - 4sqrt3#

#= 2sqrt3#