How do you simplify #2 sqrt11 + sqrt44#?

1 Answer
Burglar
Jun 5, 2016

Writing #44# as product of its factors.

Explanation:

To simplify this you have to search for something you cah do in the square root. You can notice that #44=11*4# then we have

#sqrt(44)=sqrt(11*4)#

and we know that we can separate the square root of a product in the product of the square roots (be careful with this rule, it is valid only for multiplications and divisions, not for sum and subtraction).

#sqrt(44)=sqrt(11*4)=sqrt(11)sqrt(4)=2sqrt(11)#

Then we have the initial expression:

#2sqrt(11)+sqrt(44)#

and now I substitute what I obtained for #sqrt(44)#

#2sqrt(11)+sqrt(44)=2sqrt(11)+2sqrt(11)=2(2sqrt(11))=4sqrt(11)#.

Related questions
See all questions in Addition and Subtraction of Radicals
Impact of this question
2154 views around the world
You can reuse this answer
Creative Commons License