How do you simplify 2/(sqrt3-2)2√3−2? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer P dilip_k Mar 10, 2016 -(4+2sqrt3)−(4+2√3) Explanation: 2/(sqrt3-22√3−2 =(2(sqrt3+2))/((sqrt3-2)(sqrt3+2))=2(√3+2)(√3−2)(√3+2) =(2(sqrt3+2))/((sqrt3)^2-2^2)=2(√3+2)(√3)2−22 =(2(sqrt3+2))/(3-4)=2(√3+2)3−4 -(4+2sqrt3)−(4+2√3) Answer link Related questions How do you simplify \frac{2}{\sqrt{3}}2√3? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify 7/(""^3sqrt(5)73√5? How do you multiply (sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))(√a+√b)(√a−√b)? How do you rationalize the denominator for \frac{2x}{\sqrt{5}x}2x√5x? Do you always have to rationalize the denominator? How do you simplify sqrt(5)sqrt(15)√5√15? How do you simplify (7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))(7√13+2√6)(2√3+3√6)? See all questions in Multiplication and Division of Radicals Impact of this question 1511 views around the world You can reuse this answer Creative Commons License