How do you simplify #(2+sqrtx)(8+sqrtx)#?

1 Answer
Jan 23, 2017

Answer:

#16+10sqrtx+x#

Explanation:

Each term in the second bracket must be multiplied by each term in the first bracket. This can be achieved as follows.

#rArr(color(red)(2+sqrtx))(8+sqrtx)#

#=color(red)(2)(8+sqrtx)color(red)(+sqrtx)(8+sqrtx)#

distribute the brackets.

#rArr16+2sqrtx+8sqrtx+(sqrtx xxsqrtx)#

#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(sqrtx xxsqrtx=x)color(white)(2/2)|)))#

collecting like terms and simplifying.

#=16+10sqrtx+x#