How do you simplify #(2+sqrtx)(8+sqrtx)#?
1 Answer
Jan 23, 2017
Explanation:
Each term in the second bracket must be multiplied by each term in the first bracket. This can be achieved as follows.
#rArr(color(red)(2+sqrtx))(8+sqrtx)#
#=color(red)(2)(8+sqrtx)color(red)(+sqrtx)(8+sqrtx)# distribute the brackets.
#rArr16+2sqrtx+8sqrtx+(sqrtx xxsqrtx)#
#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(sqrtx xxsqrtx=x)color(white)(2/2)|)))# collecting like terms and simplifying.
#=16+10sqrtx+x#