# How do you simplify #20 / (3+i)#?

##### 1 Answer

Dec 16, 2015

Multiply both numerator and denominator by the Complex conjugate

#20/(3+i) = 6-2i#

#### Explanation:

#20/(3+i)#

#= (20(3-i))/((3+i)(3-i))#

#= (20(3-i))/(3^2+1)#

#= (20(3-i))/10#

#=6-2i#