How do you simplify #200/sqrt5#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Aviv S. Mar 10, 2018 The result is #40sqrt5#. Explanation: Factor #200#, separate the fraction, then combine the exponents: # color(blue)200/sqrt5 # # color(blue)200/(5^(1/2)) # # color(blue)200*1/(5^(1/2)) # # color(blue)200*5^(-1/2) # # color(blue)(40*5)*5^(-1/2) # # color(blue)(40*5^1)*5^(-1/2) # # color(blue)40*5^(1-1/2) # # color(blue)40*5^(1/2) # # color(blue)40*sqrt5 # # color(blue)40sqrt5 # Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1654 views around the world You can reuse this answer Creative Commons License