# How do you simplify (25+15i)-(25-6i) and write the complex number in standard form?

May 4, 2018

$21 i$

#### Explanation:

Standard form: $a + b i \rightarrow a$ is real

$\left(25 + 15 i\right) - \left(25 - 6 i\right) \rightarrow$ Distribute the negative

$25 + 15 i - 25 - \left(- 6 i\right)$

$25 + 15 i - 25 + 6 i \rightarrow$ Combine like terms

$0 + 21 i$

$21 i$