# How do you simplify (-28-16i )/( 1-5i)?

Dec 2, 2015

$2 - 6 i$

#### Explanation:

Multiply both denominator and numerator by the conjugate of the denominator

$z = 1 - 5 i$

$\overline{z} = 1 + 5 i$

$\frac{\left(- 28 - 16 i\right) \left(1 + 5 i\right)}{\left(1 - 5 i\right) \left(1 + 5 i\right)}$

$\frac{- 28 - 28 \cdot 5 i - 16 i + 16 \cdot 5}{1 + 25}$

$\frac{52 - 156 i}{26}$

$2 - 6 i$