How do you simplify #(-28-16i )/( 1-5i)#?

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Answer 1 · 2015-12-02T00:28:06

#2-6i#

Multiply both denominator and numerator by the conjugate of the denominator

#z = 1-5i#

#barz = 1+5i#

#((-28-16i)(1+5i))/((1-5i)(1+5i))#

#(-28-28*5i-16i+16*5)/(1+25)#

#(52-156i)/26#

#2-6i#