Question

How do you simplify `(2i)/(1-i)` and write the complex number in standard form?

Answer 1

`= -1 + i`

Explanation:

multilply by the conjugate of the denominator

that gives you

`(2i)/(1-i) * (1+i)/(1+i)`

`= (2i(1+i))/(2)`

`= (2i-2)/(2)`

`= -1 + i`