How do you simplify #2sqrt5(4-3sqrt5)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Don't Memorise Dec 15, 2015 # =color(blue)( 8sqrt5 -30# Explanation: #color(blue)(2sqrt5) * (4 - 3sqrt5)# # = color(blue)(2 * sqrt5) * (4 ) +color(blue)(2sqrt5) *(- 3sqrt5)# # = 2* 4 (sqrt5) + (2) * (- 3) * sqrt5 * sqrt5# # = 8sqrt5 -6 * sqrt5 * sqrt5# # = 8sqrt5 -6 *5# # =color(blue)( 8sqrt5 -30# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1332 views around the world You can reuse this answer Creative Commons License