How do you simplify (2sqrt7+4)^2?

$44 + 16 \sqrt{7}$
To simplify use the algebraic identity ${\left(a + b\right)}^{2}$= ${a}^{2} + 2 a b + {b}^{2}$.
It would give ${\left(2 \sqrt{7}\right)}^{2} + 2 \left(2 \sqrt{7}\right) \left(4\right) + {\left(4\right)}^{2} = 44 + 16 \sqrt{7}$