Question

How do you simplify `(2u v ^ { 3} \cdot 3u v ^ { - 1} ) ^ { 2}`?

Answer 1

`36u^4v^4`

Explanation:

Evaluate the contents of the bracket before ' squaring'

Using the `color(blue)"laws of exponents"`

`color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(a^mxxa^n=a^(m+n))color(white)(2/2)|)))`

`rArr2u^1v^3xx3u^1v^-1=(2xx3)xxu^(1+1)v^(3-1)=6u^2v^2`

now evaluate `(6u^2v^2)^2`

`=6u^2v^2xx6u^2v^2=36u^4v^4`