How do you simplify (2x^2-10)/(x+1)*(x+2)/(3x^2-15)?

$\frac{2 \left(x + 2\right)}{x + 1}$
$\frac{2 {x}^{2} - 10}{x + 1} \cdot \frac{x + 2}{3 {x}^{2} - 15}$
$\frac{2 \left(\cancel{{x}^{2} - 5}\right)}{x + 1} \cdot \frac{x + 2}{\cancel{3 \left({x}^{2} - 5\right)}} = \frac{2 \left(x + 2\right)}{x + 1}$