How do you simplify #2x y ^ { 0} \cdot x ^ { 3} y ^ { 4}#?

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Answer 1 · 2018-05-12T20:15:25

#2x^4y^4#

#2xy^0 * x^3y^4#

First, we know that anything to the power of #0# is #1#, meaning that #y^0 = 1#.

So the expression becomes:
#2x(1) * x^3y^4#

#=> 2x * x^3 y^4#

When you multiply two bases which both have exponents, you add the exponents.

#x * x^3 = x^(1+3) = x^4#

So the expression becomes:
#2x^4y^4#

Hope this helps!