How do you simplify #(2x)/(y²) * (3y³)/(4x²)#?

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Answer 1 · 2015-07-25T11:32:39

Cancel equal terms from the numerator and the denominator.

Your starting expression looks like this

#(2x)/(y^2) * (3y^3)/(4x^2)#

You know that you can write #3y^3# and #4x^2# as

#3y^3 = 3y^2 * y#

#4x^2 = (2x)^2 = 2x * 2x#

Your expression now becomes

#cancel(2x)/cancel(y^2) * (3 * cancel(y^2) * y)/(cancel(2x) * 2x) = color(green)((3y)/(2x))#