# How do you simplify (3-2i)/(-4-i)?

Feb 17, 2017

$\frac{- 10 + 11 i}{17}$
$\frac{3 - 2 i}{- 4 - i} \cdot \frac{- 4 + i}{- 4 + i}$
remember that $\textcolor{\mathmr{and} a n \ge}{{i}^{2} = - 1}$
$\frac{- 12 + 3 i + 8 i - 2 {i}^{2}}{16 - 4 i + 4 i - {i}^{2}} = \frac{- 12 + 11 i - 2 \left(- 1\right)}{16 - \left(- 1\right)} = \frac{- 10 + 11 i}{17}$