How do you simplify (3-2i)/(-4-i)? Precalculus Complex Numbers in Trigonometric Form Division of Complex Numbers 1 Answer Lithia Feb 17, 2017 (-10+11i)/17 Explanation: (3-2i)/(-4-i) * (-4+i)/(-4+i) multiply by its conjugate remember that color(orange)(i^2=-1) (-12+3i+8i-2i^2)/(16-4i+4i-i^2)=(-12+11i-2(-1))/(16-(-1))=(-10+11i)/17 Answer link Related questions How do I graphically divide complex numbers? How do I divide complex numbers in standard form? How do I find the quotient of two complex numbers in polar form? How do I find the quotient (-5+i)/(-7+i)? How do I find the quotient of two complex numbers in standard form? What is the complex conjugate of a complex number? How do I find the complex conjugate of 12/(5i)? How do I rationalize the denominator of a complex quotient? How do I divide 6(cos^circ 60+i\ sin60^circ) by 3(cos^circ 90+i\ sin90^circ)? How do you write (-2i) / (4-2i) in the "a+bi" form? See all questions in Division of Complex Numbers Impact of this question 11707 views around the world You can reuse this answer Creative Commons License