How do you simplify $(3 + 2 i) + (6 - i)$ $(3 + 2i) + (6 - i)$ ?

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How do you simplify $(3 + 2 i) + (6 - i)$ $(3 + 2i) + (6 - i)$ ?

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Answer 1 · 2016-01-09T14:19:27

I found: $9 + i$ $9+i$

Explanation:

We first get rid of the brackets:
$3 + 2 i + 6 - i =$ $3+2i+6-i=$
Then we add real and immaginary parts:
$= (3 + 6) + (2 i - i) =$ $=(3+6)+(2i-i)=$
$= 9 + i$ $=9+i$

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How do you simplify $(3 + 2 i) + (6 - i)$ $(3 + 2i) + (6 - i)$ ?

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How do you simplify $(3 + 2 i) + (6 - i)$ $(3 + 2i) + (6 - i)$ ?