How do you simplify #(3-3i)/i#?
1 Answer
Sep 6, 2016
Explanation:
#=((3-3i)i)/i^2#
#=(3i-3i^2)/(-1)#
#-(3i-3(-1))#
#=-(3+3i)#
#=-3-3i#
#=((3-3i)i)/i^2#
#=(3i-3i^2)/(-1)#
#-(3i-3(-1))#
#=-(3+3i)#
#=-3-3i#