How do you simplify #(3+8i)/(-3-i)#?

1 Answer
Mar 15, 2016

The final answer is: (-17/10) - (21i/10).


To solve this questions you can first square the "-3" in the denominator to get 9. Then you square the coefficient of i, which would be 1. You then add the 9 and 1 to get 10. Now you know that 10 will be the denominator for your final answer to the question.

Next, you multiple the numerator of the fraction by the complex conjugate of the denominator, which would be -3 + i.

After you foil out the top, you simplify and break the numerator into two parts, one real and one imaginary.

The final answer would be: (-17/10) - (21i/10).